Question: i need help with part c, also how is part a&b looking? 10:217 il 5G Part 1: what molarity is my kool aid Weight of

i need help with part c, also how is part a&b looking?
i need help with part c, also how is part a&b looking?

10:217 il 5G Part 1: what molarity is my kool aid Weight of Kool-aid:5.00g or 1.853 mole 5/26.98=1.583 mole M=n/L 20M= 1.583/0.9266 Questions: Part 1: A) How many moles of Kool-Aid are needed? Show your work 5g/26.98g=1.583 mole B)Since the primary ingredient in Kool Aid is citric acid, for purposes of this activity we will assume that the Kool Aid is "pure" citric acid. The formula for citric acid is What is the molar mass of citric acid? Show your work Citric acid formula is CHO, C:12.011x6=72.066 H:1.0080x8=8.0640 0:16.00x7=112.00 molar mass: 192.13 mole C)Use the molar mass of citric acid and the moles of Kool-Aid (calculated in question a) to determine the mass of Kool-Aid powder. Show your work

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Chemical Engineering Questions!