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Show how to use the Intermediate Value Theorem to show that the equation 2:2 v 3 = 5 has a solution between 0 and 3. Let f(:z:) = 3:2 V 33:. In order for the Intermediate Value Theorem to apply we must first check that f is on the interval [0,3]. You should verify this and be able to explain why it is the case. We check the value of f at the left endpoint of the interval [0,3]