I need help with step 2 of the problem.

Tutorial Exercise A vertical spring stretches 3.7 cm when a 13-g object is hung from it. The object is replaced with a block of mass 27 g that oscillates up and down in simple harmonic motion. Calculate the period of motion. Step 1 A simple harmonic oscillator moves under the influence of Hooke's law with force F = -kx where x is the displacement from equilibrium. The spring constant k is given by the following equation. 'T S k = X When an object of mass m = 13 g hangs from the spring, the force stretching the spring is Fs = mg = 13 3 x 10-3 kg) (9.80 m/s2) = 0.1274 0.127 N. Step 2 If this force of magnitude F produces an elongation x, the spring constant is N K = N/m. X m