Question: I need help with the matlab code for this question. 41.1 The length of the curved part of a unit semicircle is . We can
41.1 The length of the curved part of a unit semicircle is . We can approximate by using triangles and elementary mathematics. Consider the semicircle with the arc bisected as in Figure (a). The hypotenuse of the right triangle is 2. Hence, a rough approximation to is given by 2V2 2.8284. In Figure (b), we consider an angle that is a fraction 1/k of the semicircle. The secant shown has length 2 sin(0/2), and so an approximation to is 2k sin(/2). From trigonometry, we have , sin 2 +2V1-sin2 2 sin(0/2) Now let On, be the angle that results from division of the semicircular arc into 2"- pieces. Next let S,, = sin, th and F, = 2nVSn+1. Show that Sn+1 = Sn/(2 + 2M-S, ) and 1 and P = 2, compute Sn+1 and P, , is an approximation to . Starting with S2 recursively for 2 s n s 20
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
