I need help with this, please.

1. Ah elevator shown below lled Iwith passengers has a mass of 1950 kg. The elevator does r'iotior's la} through (c) in successior'. For each of the oar.s below cl raw a free bod}.r diagram of the elevator in your notebook For each of the parts {a] to (c). Draw the acceleration and velocity vectors in the boxes. For each part, are the vectors for tension in the string and weight ofthe elevator of equal Ier'gths or unequal lengths. m {a} The elevator accelerates upward from rest at a rate of 1.55 2 for 1.[|'5 s. E {i}I New:on's Second Law in the v-direction can be written as: instruction: HE is the magnitude of the acceleration, pick "1" if the acceleration is upwards, pick "1 " if the acceleration is downwards, and pick "D" if there is no acceleration. zs= To = m.a [ii} Calculate the tension in the cable supporting the elevator. -=|:o~ {iii}I Hov.l high has the elevator moved during this time? y=| Elm {ii} Calculate the tension in the cable supporting the elevator. T=|:Eii~' {Hi} How high has the elevator moved during this time? y: | Eam- {iv} Calculate the velocit_v ofthe elevator after this time. at v{1=1.s]=| 5' Eb] The elevator contir'ues upward at constant velocity for 3.55 s. {i} NeWton's Law in the v-direction can be written as: Instruction: Ifa is the magnitude of the acceleration, pick "1" if the acceleration is upwards, pick "1 " if the acceleration is downwards, and pick "D" if there is no acceleration. {ii} Calculate the tension in the cable supporting the elevator. r=|:ri~ {iii} How high has the elevator moved during this time? y: | [im- in Kc] The elevator decelerates at a rate of [LE 2 For 2.?5 s. s {i} NeWton's Law in the v-direction can be written as: Instruction: Ifa is the magnitude of the acceleration, pick "'1" ifthe acceleration is upwards, pick "1 " if the acceleration is downwards, and pick "D" if the re is no acceleration. {ii} Calculate the tension in the cable supporting the elevator. r=|:o~ {iii} How high has the elevator moved during this time? y=| Eam- Ed] What is the total distance the elevator has moved up? Reect: Ir' which case is the tension in the chord pulling the elevator the greateE? Why? Does the tension always equal the weight oFthe elevator