I need help writing this BASH shell script:

Write a BASH shell script that acts as a DOS command interpreter (the user enters the DOS command and the script executes the corresponding Linux command).

The script should loop continuously until the user enters the QUIT command

Prior to accepting a command, display a prompt containing your first name and the greater than symbol (>)

Example prompt: linux>

The DOS command, and any arguments, should be stored in variables

$command the DOS command (required)

$arg1 the first argument (optional)

$arg2 the second argument (optional) Note: Only some DOS/Linux commands will require one or both argument variables.

The script should use case statements to select the appropriate Linux command

If an unknown DOS command is entered, display the error message, Command Not Found!

Refer to the table below for a list of DOS commands and their Linux counterparts (COMMAND [ARG 1] [ARG 2])

DOS Command *	Linux Command
CHDIR [target directory]	cd [target directory]
CLS	clear
COPY [source file] [destination file]	cp [source file] [destination file]
CREATEDIR [directory name]	mkdir [directory name]
CREATEFILE [file name]	touch [file name]
DELETE [file name]	rm [file name]
DIR [file name | directory name | wildcard]	ls [file name | directory name | wildcard]
MOVE [source] [destination]	mv [source] [destination]
PRINT [message to print]	echo [message to print]
QUIT	N/A
RENAME [old name] [new name]	mv [old name] [new name]
TYPE [file name]	cat [file name]
* Assume DOS commands are case-insensitive (i.e., DIR is the same as dir).

Thanks