Question: I need some help with this problem: A proton moves through a uniform magnetic field given by B=(15.0i^25.4j^+12.7k^) mT. At time t 1 , the
I need some help with this problem:
A proton moves through a uniform magnetic field given by B=(15.0i^25.4j^+12.7k^) mT. At time t1, the proton has a velocity given by v=vxi^+vyj^+(1.94km/s)k^ and the magnetic force on the proton is FB=(5.331017N)i^+(3.151017N)j^ . (a) At that instant, what is vx? (b) At that instant, what is vy?
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
