A proton moves through a uniform magnetic field given by B $=(15\mathrm{.}01-25\mathrm{.}4$j $+12\mathrm{.}7$k$)$ mT$.$ At time t$1,$ the proton has a velocity given by v $=$ vx i $+$ v$,$ j $+(1\mathrm{.}94$ km$/$s$)$ k and the magnetic force on the proton is F B $=(5\mathrm{.}3310-17$ N$),$ i $+(3\mathrm{.}15$ x $10-17$ N$)$ j$.($a$)$ At that instant, what is vx$?($b$)$ At that instant, what is vy$?$