3- The first iteration of the Fixed point method to solve the following system near (0.8,0.4)...

Transcribed Image Text:

3- The first iteration of the Fixed point method to solve the following system near (0.8,0.4) x-x2 - y2 0 y - x2 + y? = 0 a) (0.6 , 0.5) b) (0.8 , 0.5) c) (0.7,0.04) d) ( 0.06, 0.05) 4- If x (1.25, 0.02, -5.15, 0), ||x|l = a) 5.15 b) 5.8 c) 6.4 d) 28 5- By using Bisection method to find a root of the equation x3 - 4x – 8.95 = 0, a root lies between a) a=0 and b=1 b) a=1 and b=2 c) a=2 and b=3 d) a=3 and b-4 3- The first iteration of the Fixed point method to solve the following system near (0.8,0.4) x-x2 - y2 0 y - x2 + y? = 0 a) (0.6 , 0.5) b) (0.8 , 0.5) c) (0.7,0.04) d) ( 0.06, 0.05) 4- If x (1.25, 0.02, -5.15, 0), ||x|l = a) 5.15 b) 5.8 c) 6.4 d) 28 5- By using Bisection method to find a root of the equation x3 - 4x – 8.95 = 0, a root lies between a) a=0 and b=1 b) a=1 and b=2 c) a=2 and b=3 d) a=3 and b-4