Question: I need this done java Programming. In the simplest way possible. Section 3.2 (Algebra: solve quadratic equations) The two roots of a quadratic equation ax2

I need this done java Programming. In the simplest way possible.  I need this done java Programming. In the simplest way possible.

Section 3.2 (Algebra: solve quadratic equations) The two roots of a quadratic equation ax2 + bx + c-0 can be obtained using the following formula: *3.1 and 2 2a 2a b-4ac is called the discriminant of the quadratic equation. If it is positive, the equation has two real roots. If it is zero, the equation has one root. If it is negative, the equation has no real roots. Write a program that prompts the user to enter values for a, b, and c and displays the result based on the discriminant. If the discriminant is positive, display two roots. If the discriminant is 0, display one root. Otherwise, display "The equation has no real roots". Note that you can use Math.pow(x, 0.5) to compute Vx. Here are some sample runs. Enter a, b, c: 1.0 3 1 Enter The equation has two roots -0.381966 and -2.61803 Enter a, b, c: 1 2.0 1 Enter The equation has one root -1 Enter a, b, c: 1 2 3 Enter The equation has no real roots

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