Question: I was able to answe the first 4 , I am stuck on 5 . What is the p H of a 0 . 0

I was able to answe the first 4, I am stuck on 5. What is the pH of a 0.050M ammonia (NH3) solution? (Kb=1.8**10-5)
What is the pH of a solution where 50.0mL of 0.050MNH3 is mixed with 12.0
mL of 0.10M hydrobromic acid (HBr)?
What is the pH at the 12 equivalence point?
What is the pH of a titration of 50.0mL of 0.050MNH3 with 0.10MHBr once
the equivalence point is reached?
(HINT: Start by calculating the volume of HBr needed to reach the equivalence point.)
What is the pH of a solution where 50.0mL of 0.050MNH3 is mixed with 25.1
mL of 0.10MHBr?
B-+H2OHB+OH,x20.05,=1.810-5
0.05m+x+x,0.05
-x,x,=9.48610-4
-log(x),=3.02pOH
14,-3.02=10.98pH
[2.]
HBr+NH3NH4+Br
D. nolzmel 0.00sna 0.,NH3=0.021M
0,00120(mol)0,00120.0013(mol)0.0621+0,0012md0,0012(mol),NH4=0.019M
POH =-log(1.810-5)+log(0.0210.019)
polt =4,78
pH=9,22
110-141.810-5=5.5610-10=kq
-log(5.5610-10)=9.26pH
c.0025md0.075(L)=0.033m,110-4011.610-3=5.5610-10,-1ng(1x)
=5.37pH
[5]NH3+HBrNHY
0,0025e,002s1
-0,002500,00250,00001,t0,00250.0025(
 I was able to answe the first 4, I am stuck

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