I would appreciated if you could check any errors from my physics lab answers.

Especially question number 3, please.

Thank you.

1.Select three examples from the choices above. In the space below, show how you applied the equation for light diffraction by a grating.

The chosen examples are as below.

• Diffraction Grating N= 100lines/mm= lines/m & wavelength =40510nm(violet)
• N=300lines/m & =53210nm(green)
• N=600lines/m & =63510nm(red)

Diffraction grating formula is dsin=m. Here, m=1 and d=1/N

• The wavelength of the violet line can be from 395nm to 415nm. So the angle can be gotten between two values 1) or 2).

1)options=n/d=1*(395E-9)/d=1*(395E-9)*N=1*(395E-9)*(10^5) =395E-4

=2.26

2) sin=n/d=1*(415E-9)/d=1*(415E-9)*(10^5) =415E-4

=2.38

• The wavelength of the green line can be 522nm to 542nm.

1) sin=n/d=1*(522E-9)/d=1*(522E-9)*N=1*(522E-9)*(3E5) =0.1566

=9.01

2) sin=n/d=1*(542E-9)/d=1*(542E-9)*(3E5)=0.1626

=9.36

• The wavelength of the red line can be 625nm to 645nm.

1) sin=n/d=1*(625E-9)/d=1*(625E-9)*N=1*(625E-9)*(6E5)=0.375

=22.0

2) sin=n/d=1*(645E-9)/d=1*(645E-9)*(6E5)=0.387

=22.8 2.Does increasing the frequency of the wave cause the light to be diffracted more, or less? Use evidence from the videos above to support this.

The diffraction rates from the three sources of different wavelengths can be measured as below.

( SCREEN CAPTURED PHOTOS)

• Violet line: wavelength =40510nm & diffraction angle =23.5
• Green line: wavelength =53210nm & diffraction angle =32
• Red line: wavelength =63510nm &diffraction angle =40

If frequency increases, wavelength decreases. So, the angle of diffraction decreases. For evidence, we can see that when changes from 532nm to 405nm, the angle of diffraction changes from 32 to 23.5. So, with an increase in frequency, the angle of diffraction decreases. Also, we can see the fact from the equation w sin = m.

3. Simon, a physics student, has an idea. He wants to build a device that will let him see around corners. He suggests that if he places a diffraction grating around a corner it would bend the light towards his eyes and he could see it.

Using evidence from these videos, state why you think this would or would not be possible.

It would not be possible to see around the corner because the light would be split like the light from a double slit when it is received from the corner. The split lights make people difficult to see the corner.

4. Determine the line spacing for this diffraction grating. Describe your process and results in the space below.

dsin=

Here d is line spacing, and lambda is the wavelength for violet light.

= 405 nm

We can measure =13

dsin13=405nm

d = 1800.39165045 nm=1.80m

Hence, the line spacing between the diffraction grafting is d=1.80m.