Identification.

When power is first applied

to any FF circuit it is

impossible to predict the

initial states of Q and Q$^(\text{'}).$

The CLK input will affect the

FF output only when the

active transition of the

control input occurs.

A JK FF cannot be used as an

SCFF$.$

The Q output will equal the

level at the D input at all

times.

AD latch is in its transparent

mode when EN$=0$

In a D latch, the D input can

affect Q only when EN$=1.$

Asynchronous data transfer

uses the CLK input.

Synchronous data transfer

requires less circuitry than

asynchronous transfer.

The fastest method for

transferring data from one

register to another is parallel

transfer.

V$.$ Waveform $(20$ points$)$

If Q$=0$ initially, draw the Q waveform response of the given FF if it is activated at

a$.$ NGT

b$.$ PGT and Q$=0$ initially