identify the syntax and logical errors in the code. 

 

def print_pattern():
    prev2 = 0
    prev = 1
    print(prev)
    for i in range(3, rows + 2):
    for j in range(i):
            nextVal = prev2 + prev
            print(nextVal, end=' ')
            prev2 = prev
            prev = nextVal


print('Display pattern...')
num == 1
while num > 0
    num = int(input('Enter the number of rows, 0 to exit: '))
    if num > 0:
        print_pattern(num)

 

The expected output is:

 

Display pattern.
Enter the number of rows, 0 to exit: 4
1
1 2
3 5 8
13 21 34 55

Answer rating: 100% (QA)

There are several syntax and logical errors in the provided code Heres the corrected version python def printpatternrows prev2 0 prev 1 printprev for ... View the full answer