Question: If A, B, and C are lambda expressions, then by associativity, ABC is a short form of A(BC) T or F (y|yz)b is a shorter,
If A, B, and C are lambda expressions, then by associativity, ABC is a short form of A(BC) T or F
(y|yz)b is a shorter, but equivalent way of writing ((y|(yz))b) T or F
((x|s(sx))x) is equivalent to ((y|s(sy))y) T or F
(y|sy)x is in normal form T or F
These questions are about LISP
please explain the reason
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