Question: If a temperature increase from 12.0Cto 21.0Cdoubles the rate constant for a reaction, what is the value of the activation barrier for the reaction? Can

If a temperature increase from 12.0°Cto 21.0°Cdoubles the rate constant for a reaction, what is the value of the activation barrier for the reaction?

Can someone please show me how to do the steps mathematically? Because I keep putting it in the equation and I'm getting numbers in the decimals. So, I guess I'm not dividing correctly.

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To calculate the activation energy barrier you can use the Arrhenius equation which relates the rate ... View full answer

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