Question: If an object is dropped from a 172-foot-high building, its position (in feet above the ground) is given by s(t) = - 16t +

If an object is dropped from a 172-foot-high building, its position (in

If an object is dropped from a 172-foot-high building, its position (in feet above the ground) is given by s(t) = - 16t + 172, where t is the time in seconds since it was dropped. (a) What is its velocity 1 second after being dropped? (b) When will it hit the ground? (c) What is its velocity upon impact? (a) The object's velocity 1 second after being dropped is (Simplify your answer.) (b) The object will hit the ground in sec. (Round to the nearest tenth as needed.) (c) The object's velocity upon impact is (Round to the nearest tenth as needed.) sec GAARD sec If an object is dropped from a 172-foot-high building, its position (in feet above the ground) is given by s(t) = - 16t + 172, where t is the time in seconds since it was dropped. (a) What is its velocity 1 second after being dropped? (b) When will it hit the ground? (c) What is its velocity upon impact? (a) The object's velocity 1 second after being dropped is (Simplify your answer.) (b) The object will hit the ground in sec. (Round to the nearest tenth as needed.) (c) The object's velocity upon impact is (Round to the nearest tenth as needed.) sec GAARD sec

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