Question: If an object is dropped from a 196-foot-high building, its position (in feet above the ground) is given by s(t) = - 16t- + 196,

If an object is dropped from a 196-foot-high building, its position (in feet above the ground) is given by s(t) = - 16t- + 196, where t is the time in seconds since it was dropped a. What is its velocity 1 second after being dropped? b. When will it hit the ground? c. What is its velocity upon impact? The object's velocity 1 second after being dropped is ft sec (Simplify your answer.) The object will hit the ground in sec. Question Viewer (Round to the nearest tenth as needed.) The object's velocity upon impact is ft sec (Round to the nearest tenth as needed.) Enter your answer in each of the answer boxes ? Sample Tests and Quizzes

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