If $C(x)=300010x-0\mathrm{.}05x^2$ then find the marginal average cost function $C^{\text{'}}$ are $(x).$

$C^{\text{'}}=(x)=-\frac{3000}{x^2}-0\mathrm{.}05$

$C_{-}^{\text{'}}(x)-\frac{3000}{x}10-0\mathrm{.}05x$

$C_{-}-(x)=\frac{10}{x}-0\mathrm{.}1$

$C_{-m}(x)=10-0\mathrm{.}1x$

$C_{-}^{\text{'}}(x)=300010x-0\mathrm{.}05x^2$