Using the substitution: $u=x-3.Re-$write the indefinite integral then evaluate $in$ terms $ofu.$

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{x^2}{\sqrt[\phantom{2}]{x-3}}dx={\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}=$

Note: answer should $bein$ terms $ofu$ only

Part $2.$

Back substituting $in$ the antiderivative you found $in$ Part $1.$ above $we$ have

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{x^2}{\sqrt[\phantom{2}]{x-3}}dx=$

Note: answer should $bein$ terms $ofx$ only