Question: If f ( epsi ) = sin ( epsi ) then, using Taylor s theorem, f = epsi 1 2 epsi

If f(\epsi )=sin(\epsi ) then, using Taylors theorem, f =\epsi 12\epsi 2sin(\xi ). Thus, lim\epsi 0(f/\epsi )=1, and from this it follows that f = O(\epsi ).

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