If $f(x)=4x^2-5x+5,$ find $f^{\text{'}}(-3).$

Use this to find the equation of the tangent line to the parabola $y=4x^2-5x+5$ at the point $(-3,56).$ The equation of this tangent line can be written in the form $y=mx+b$

where $m$ is:

and where $b$ is: