Question: If ln (x^2 - 24y) = x - y + 6 and y(-5) = 1, find y'(-5) by implicit differentiation. Thus the equation of the

If ln (x^2 - 24y) = x - y + 6 and y(-5) = 1, find y'(-5) by implicit differentiation. Thus the equation of the tangent line to the graph at the point (-5, 1) is y =

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