Question: If ln (x^2 - 24y) = x - y + 6 and y(-5) = 1, find y'(-5) by implicit differentiation. Thus the equation of the
If ln (x^2 - 24y) = x - y + 6 and y(-5) = 1, find y'(-5) by implicit differentiation. Thus the equation of the tangent line to the graph at the point (-5, 1) is y =
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
