Question: if n = 10000, the answer should look like this, but the number of steps is wrong for the following code, the following code gets

 if n = 10000, the answer should look like this, but

if n = 10000, the answer should look like this, but the number of steps is wrong for the following code, the following code gets 10000 steps, while it should be 56971 steps. Can you please help to get the right code? Thank you.

the number of steps is wrong for the following code, the following

code gets 10000 steps, while it should be 56971 steps. Can you

Consider the number 220 Find the sum of factors, except the number itself (also called proper divisors) 220=1+2+4+5+10+11+20+44+55+110=284 Now find the sum of factors for 284 284=1+2+4+71+142=220 220 and 284 are called the Pairs Write a Python program that 1. prints all the pairs 2. number of steps took to compute pairs \#\# s= Solution(n,a) \#\#All action happens here \#\# a[0]= How many pairs are there in n. Use_increment_number_of_pairs to fill \#\# a[1] = num_steps . Use_increment_steps class Solution: def_init_(self,n:'int',a:'list of size 2 '): self._n n=n \#\# s = Solution(n,a) \#AAll action happens here \#\# a[0]= How many pairs are there in n. Use increment_number_of_pairs to fill \#\# a[1] = num_steps Use _increment_steps self._list =a \#\# You can have any number of data structures here \#\# Nothing can be changed below self._alg() def_increment_steps(self)->'none': self._list[1] = self._list[1]+ 1 def_increment_number_of_pairs(self)->"int": self._list [0]= self._list [0]+1 return (self._list[0]) \#\#You can have any number of private variables and functions def_alg(self): print("Code") print("Use as many small functions as possible") \# Implement your code here

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