Question: If the following code appears in a class, it won't compile. Why? public static void main(String[] args) { throw new Exception(Hi!); } A. Java doesn't

If the following code appears in a class, it won't compile. Why?

 public static void main(String[] args) { throw new Exception("Hi!"); } 

A. Java doesn't allow throwing Exceptions

B. The Exception constructor doesn't take an argument

C.The Exception class is "checked" so you must write throws Exception after (String[] args)

D. If a Java program is guaranteed to throw an exception, Java won't allow it to compile

Im thinking its C right?

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