Question: If the following code appears in a class, it won't compile. Why? public static void main(String[] args) { throw new Exception(Hi!); } A. Java doesn't
If the following code appears in a class, it won't compile. Why?
public static void main(String[] args) { throw new Exception("Hi!"); } | A. Java doesn't allow throwing Exceptions |
| B. The Exception constructor doesn't take an argument |
| C.The Exception class is "checked" so you must write throws Exception after (String[] args) |
| D. If a Java program is guaranteed to throw an exception, Java won't allow it to compile |
Im thinking its C right?
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