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For the truss shown above, $x1=3m,x2=2\mathrm{.}1m,y1=2\mathrm{.}5m$ and $y2=y1(\frac{x2}{x1}).($Figure

is NOT to scale$).$ The bolded members $(AB$ and $BC)$ have a weight per unit length

of $W=9k\frac{N}{m},$ and all other members have negligible weight. The magnitude of

the applied forces are $P1=5kN$ and $P2=12kN.$

Solve for the force in members $AB,BD,$ and $,$ and $\{$:$F_{DE}).$

Using the convention that tension forces are positive and compression forces are

negative, solve the equation $Z=-F_{AB}+F_{BD}+F_{DE}.$

Write your final answer for $Z$ in $kN$ units in the answer box below. Round your

answer to two decimal places.

Hint: Here is a method to solve, whilst checking if your answer is correct as you

go:

Take moments about the left reaction support to find the magnitude of the

right reaction support. Then take moments about the right reaction support

to find the magnitude of the left reaction support. Then check that vertical

equilibrium correctly sums to zero.

Evaluate the left sectioned shape and then evaluate the right sectioned

shape. Confirm that you obtain the same answers using both sectioned

shapes. Perhaps even try solving the problem using Method of Joints.

When you have confirmed that you have the correct answer, complete the

algebraic equation.