1. If the random variable Z has a standard normal distribution, ZNormal(0,1), then P(Z < 2.23 ) =
2. If the random variable Z has a standard normal distribution, ZNormal(0,1), then P( -2.49 < Z < 0.51 ) =
3. If X is a normally distributed random variable with mean =159 and standard deviation =17 so that, XNormal(=159, ²=17²), then the z-score relating to the value X = 130 is
4. If X is a normally distributed random variable with mean =109 and standard deviation =12 so that, XNormal(=109, ²=12²), then P( X < 120 ) =
5. The value of Z_0.0099is
6. If the random variable X has a normal distribution with mean = 171 and standard deviation = 15, XNormal( 171 , 15²), find the value of X for which 24.2% of the population have values greater than X.

Answer = [x](2 dec places).