Question: If the yield factor is 0.60 mg biomass COD/mg substrate COD removed, calculate the amount of substrate removed after 6 hours for the data given

If the yield factor is 0.60 mg biomass COD/mg substrate COD removed, calculate the amount of substrate removed after 6 hours for the data given below. Assume that the mass of an E.colicell is 10-12 g.

The data in the table below were obtained for the growth of a pure culture of E.coliin nutrient broth at a temperature of 37 C.If the yield factor is 0.60 mg biomass COD/mg substrate COD removed,calculate the amount of substrate removed after 6 hours for the data

Time (h) 0 2 3 5 7 12 24 Bacteria 4.30 x 109 3.50 x 104 8.90 x 109 520 x 10% 260 x 106 1.60 x 107 7.10% 10% 120 x 10240 x 10 5.90 x 108 (No/mL) Turbidity 7.5 22.6 45.1 (TU) 0 0 0 0 0.4 08 204 Bacteria Turbidity 1E+09 1E+08 1E+07 1E+06 1E+05 1E+04 1E+03 1E+02 1E+01 1E+00 0 50 45 40 35 30 25 20 15 10 5 0 25 Turbidity 5 20 10 15 Time (h) From the plot, the lag phase lasted approximately 1.5 hours. The log growth phase occurred between 1.5 and 6 hours for a duration of nearly 4.5 hours. Regression of the count data between 2 and 6 hours using Eq. (6.1) yielded a slope of 1.68 h

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