Question: If y = sin1 x, then sin y = x,2 y 2. Therefore, to find y = sin132, we must find an angle y whose

If y = sin1 x, then sin y = x,2 y 2. Therefore, to find y = sin132, we must find an angle y whose sine is 32.There are many possible angles with this sine, but the range of y = sin1 x is restricted to , and so y must be in this interval.

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