If you could show the math/work that would be really helpful

Monthly usage, d = 300 Rate answe Annual usage, D = d*12 = 300*12 = 3600 Carrying cost, H = 0.5 per can per year Ordering cost, S = 15 Operating days per year = 350 Optimal ordering quantity, Q = V(2DS/H) = V(2*3600*15/0.5) = 464.76 Total inventory cost = QH/2 = 464.76*0.5/2 = 116.19 No. of times per year they should order = D/Q = 3600/464.76 = 7.75 Days between orders = Operating days per year / No. of times they order = 350/7.75 = 45.16 rounded to 45 days A new garbanzo bean supplier is offering a quantity discount schedule to Wes and Steve (see page 2). Given this information and calculations from Part 1, the pair need to determine what quantity to buy and how much it will cost (they want to minimize their purchase/inventory costs). Use this information to answer the questions on Page 2. Their canned goods source has offered a quantity discount schedule as shown below. Using this information and data from Part 1, use math from lecture to determine the quantity they should order to minimize total costs. (Math = 6 pts; answer = 2 pts) Quantity Unit Price $.60 0-349 350-599 $.50 600-1499 $.40 They should order: This quantity: Costing: 1500+ $.35