If you will, please explain though each step so that I can better understand. Thanks much.

Let x = age in years of a rural Quebec woman at the time of her first marriage. In the year 1941, the population variance of x was approximately of = 5.1. Suppose a recent study of age at first marriage for a random sample of 41 women in rural Quebec gave a sample variance $2 = 2.3. Use a 5% level of significance to test the claim that the current variance is less than 5.1. Find a 90% confidence interval for the population variance. (a) What is the level of significance? State the null and alternate hypotheses. O Ho: d? 5.1 (b) Find the value of the chi-square statistic for the sample. (Round your answer to two decimal places.) What are the degrees of freedom? What assumptions are you making about the original distribution? We assume a normal population distribution. We assume a uniform population distribution. We assume a exponential population distribution. We assume a binomial population distribution.(c) Find or estimate the P-value of the sample test statistic. O P-value > 0.100 O 0.050 a, we reject the null hypothesis. O Since the P-value s a, we reject the null hypothesis. O Since the P-value s a, we fail to reject the null hypothesis. (e) Interpret your conclusion in the context of the application. O At the 5% level of significance, there is insufficient evidence to conclude that the variance of age at first marriage is less than 5.1. O At the 5% level of significance, there is sufficient evidence to conclude that the that the variance of age at first marriage is less than 5.1. (f) Find the requested confidence interval for the population variance. (Round your answers to two decimal places.) lower limit upper limit Interpret the results in the context of the application. O We are 90% confident that o lies outside this interval. We are 90% confident that of lies below this interval. We are 90% confident that of lies within this interval. We are 90% confident that of lies above this interval