Identify the microstructure resulting from each of the following heat treatments applied to a 1080 Carbon...

  

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Identify the microstructure resulting from each of the following heat treatments applied to a 1080 Carbon Steel. Be sure to indicate approximate percentages of all phases present. Each treatment begins with Austenizing at B00 C before beginning the cooling operation (RT= room temperature), Microstructures must be described in terms of Bainite (upper, lower), Pearlite (coarse, medium, fine), Martensite (tempered if applies), spheroidite. Premise Response Drag and drop to match Quench to 650C/ hold 100s/ quench to RT. -> = A 100% Tempered Martensite Quench to 400 C/ hold 1 hour/ cool to RT. -> = B 100% Fine Pearlite What is the approximate Hardness for the component treated according to question B -> = C 100% Coarse Perlite Reheat the part in "1" to 700 Cand hold for 20 hrs. Cool to RT -> = D 575-600 BHN = E 250-300 BHN = F 100% Spheroidite = G 485-490 BHN What is the approximate Hardness for the component treated according to question B %3D 100% Coarse Perlite Reheat the part in "1" to 700 C and hold for 20 hrs. Cool to RT -> 575-600 BHN 14 = E 250-300 BHN 100% Spheroidite 485-490 BHN = H 100% Quenched Martensite 100% Bainite %3D 个 3. Identify the microstructure resulting from each of the following heat treatments applied to a 1080 Carbon Steel. Be sure to indicate approximate percentages of all phases present. Each treatment begins with Austenizing at B00 C before beginning the cooling operation (RT= room temperature), Microstructures must be described in terms of Bainite (upper, lower), Pearlite (coarse, medium, fine), Martensite (tempered if applies), spheroidite. Premise Response Drag and drop to match Quench to 650C/ hold 100s/ quench to RT. -> = A 100% Tempered Martensite Quench to 400 C/ hold 1 hour/ cool to RT. -> = B 100% Fine Pearlite What is the approximate Hardness for the component treated according to question B -> = C 100% Coarse Perlite Reheat the part in "1" to 700 Cand hold for 20 hrs. Cool to RT -> = D 575-600 BHN = E 250-300 BHN = F 100% Spheroidite = G 485-490 BHN What is the approximate Hardness for the component treated according to question B %3D 100% Coarse Perlite Reheat the part in "1" to 700 C and hold for 20 hrs. Cool to RT -> 575-600 BHN 14 = E 250-300 BHN 100% Spheroidite 485-490 BHN = H 100% Quenched Martensite 100% Bainite %3D 个 3.

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1 Quenched to 650 hold 100s cool to RT 100 fine pearlite due to the large time ... View the full answer