Make this circuit to a signal processing for a certain signal, I picked (Audio mixer as an application), the first stage will be Amplification, I used summer amplifier (multiple frequencies and voltages), then Filtratio stage, I used bandpass filler because it allows a range of frequencies to pass, after that analog to digital converter (ADC) when running the simulation there are no numbers as a digital output and the LED's are not lighting even though there are readings on the Voltmeter, So I need improvement for the circuit and to have a digital output. 

Transcribed Image Text:

V1 R5 R2 53.0516477nF 5kQ Amplification-Out Filter-output 1Vpk: 1ko 5kHz 0°: R7 VCC 10V U1 XSC1 V2 1kQ R1 .... .... .... 0.1Vpk : 1kO Ext Trig 8kHz V4 10V U2 ... R4 B ... ... 0.2Vpk 1ko 18KHZ + ... C1 R6 741 1kO VDD 741 VDD 7.957747155nF -10V XSC2 10V ..... Ext Trig ... U4 U5. A ... ... ... DCD HEX DCD_HEX U3 . ... .... ... Vin DO D1 U6 D2 0.015u DC 10MOhm .... . .. Da D4 10V D5 pe Vref+ ... ... .... . D7 Vref- Vref-. ..... X1X2X3X4 X5 X6X7X8 soc EOG V3 ADC 10kHz 5V 2.5V 2.5V 2.5V . .. 2.5%.5.5Y.5V 2.5V .... ..... . .... ... ..... ...... ... V1 R5 R2 53.0516477nF 5kQ Amplification-Out Filter-output 1Vpk: 1ko 5kHz 0°: R7 VCC 10V U1 XSC1 V2 1kQ R1 .... .... .... 0.1Vpk : 1kO Ext Trig 8kHz V4 10V U2 ... R4 B ... ... 0.2Vpk 1ko 18KHZ + ... C1 R6 741 1kO VDD 741 VDD 7.957747155nF -10V XSC2 10V ..... Ext Trig ... U4 U5. A ... ... ... DCD HEX DCD_HEX U3 . ... .... ... Vin DO D1 U6 D2 0.015u DC 10MOhm .... . .. Da D4 10V D5 pe Vref+ ... ... .... . D7 Vref- Vref-. ..... X1X2X3X4 X5 X6X7X8 soc EOG V3 ADC 10kHz 5V 2.5V 2.5V 2.5V . .. 2.5%.5.5Y.5V 2.5V .... ..... . .... ... ..... ...... ...

Answer rating: 100% (QA)

Band Pass Filters can be used to isolate or filter out certain frequencies that lie within a particular band or range of frequencies The cutoff frequency or c point in a simple RC passive filter can b... View the full answer