Question: I'M CODING IN UNIX TERMINAL ON MAC. USING TEXTMATLAB. Thanks!! 10 How to Find Basis for ROW SPACE of AB Using Column Space of (AB)t

I'M CODING IN UNIX TERMINAL ON MAC. USING TEXTMATLAB. Thanks!!

10 How to Find Basis for ROW SPACE of AB Using Column Space of (AB)t = (AB)

3 9 7 2 6 3 1 LetABbedefinedasbefore. AB= 2 6 0 8 4 12 4

Type :

ABR = rref(AB)

To see the Reduced Row-Echelon Form of AB. Use ABR to find a basis for Column space of AB

Then enter your basis vectors as:

26 518433113 9 2 8 6 18 6

Note that row space of AB = column space of (AB).

Use MATLAB to find a basis for the row space of AB consist of row vectors of AB. Then enter your basis vectors as:

% ABV1 = Type your first row vector of basis of AB % ABV2 = Type your second row vector of basis of AB % ABV3 = Type your third row vector of basis of AB

11 How to Find independent Columns of Matrix AB 3 9 7 2 6 3 1

LetABbedefinedasbefore. AB= 2 6 0 8 4 12 4 26 51843311

3 9 2

8 6 18 6

% ABW1 = Type your first column vector of basis of AB % ABW2 = Type your second column vector of basis of AB % ABW3 = Type your third column vector of basis of AB

Now type

[R1, pivcol ] = rref(AB)

This command will provide you rref(AB) and pivot columns of AB. The columns of ABthat are independent and form a basis for the column space. You can use MATLAB to give you a matrix composed of the independent columns ofAB

Type:

UAB = AB(:,pivcol)

20

12 How to Find independent Columns of Matrix AB

You may use this to find a basis for the row space: Type:

[R2, pivcol ] = rref(AB)

This command will provide you rref(AB) and pivot columns of AB which are row vec- tors of AB. The columns of AB that are independent and form a basis for the column space.

Then enter your basis vectors as:

% ABU1 = Type your first Row vector of basis of AB % ABU2 = Type your second Row vector of basis of AB % ABU3 = Type your third Row vector of basis of AB

Note that these are Rows of AB that form a basis for row space of AB.

You Can use MATLAB to give you a matrix composed of the independent rows of ABType:

C = AB UAB1 = C(:,pivcol)

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