Question: I'm having a super hard time figuring this out. I believe I have to figure out my z scores first Z= M- M/M That would

I'm having a super hard time figuring this out. I believe I have to figure out my z scores first Z= M- M/M That would be Z=73-75/2, I think

One hundred people are included in a study in which they are compared to a known population that has a mean of 73, a standard deviation of 20, and a rectangular distribution.

M = ____73______.

M = ___2_______. **This answer is NOT 20!

The shape of the comparison distribution is __________. **This answer is NOT rectangular! (How would I even determine this)

If the sample mean is 75, the lower limit for the 99% confidence interval is __________.

If the sample mean is 75, the upper limit for the 99% confidence interval is __________.

If the sample mean is 75, the lower limit for the 95% confidence interval is __________.

If the sample mean is 75, the upper limit for the 95% confidence interval is __________.

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