. The enzyme, urease, is immobilized on a 0.2 cm porous support. The Km= 0.2mM and...

 

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. The enzyme, urease, is immobilized on a 0.2 cm porous support. The Km= 0.2mM and the enzymatic rate of hydrolysis, v = 10 mol. h-¹. m³ at a bulk liquid concentration SB= 0.5mM, with an effective diffusivity of De 1.5 x10-5 cm².s-1. Neglecting liquid film resistance, determine the maximum rate of hydrolysis ("), the Thiele modulus (+) and the effectiveness factor (n). = Hint: A first estimate to the trial and error problem lies when "m=7v 1mM = 1mmol.L-1 Equations v = n VIIm[ss] K'm+[ss] 3. 1 VIIm η == Ltanho K'm De . The enzyme, urease, is immobilized on a 0.2 cm porous support. The Km= 0.2mM and the enzymatic rate of hydrolysis, v = 10 mol. h-¹. m³ at a bulk liquid concentration SB= 0.5mM, with an effective diffusivity of De 1.5 x10-5 cm².s-1. Neglecting liquid film resistance, determine the maximum rate of hydrolysis ("), the Thiele modulus (+) and the effectiveness factor (n). = Hint: A first estimate to the trial and error problem lies when "m=7v 1mM = 1mmol.L-1 Equations v = n VIIm[ss] K'm+[ss] 3. 1 VIIm η == Ltanho K'm De