Imagine you derive the following expression by analyzing the physics of a particular system:$$v$2=$v$20+2$axv$2=$v$02+2$ax$.$ The problem requires solving for$$xx$,$ and the known values for the system are a$=2\mathrm{.}55$meter$/$second$2$a$=2\mathrm{.}55$meter$/$second$2,$v$0=21\mathrm{.}8$meter$/$secondv$0=21\mathrm{.}8$meter$/$second$,$ and$$v$=0$meter$/$secondv$=0$meter$/$second$.$ Perform the next step in the analysis.$$

View Available Hint$($s$)$for Part A

v$2=(21\mathrm{.}8$meter$/$second$)2+2(2\mathrm{.}55$meter$/$second$2)$xv$2=(21\mathrm{.}8$meter$/$second$)2+2(2\mathrm{.}55$meter$/$second$2)$x$$v$2=$v$20+2$axv$2=$v$02+2$ax$($no simplification should be performed on the expression in this situation$)0=$v$20+2$ax$0=$v$02+2$ax$$