img alt$=$"Fig. $24-10$ shows three capacitors connected to a b$"$ class$=$"user$-$upload" src$="//$d$2$vlcm$61$l$7$u$1$fs$.$cloudfront.net$/$media$/89$d$/89$d$898$ac$-1273-4063-8855-2$a$151$a$6$fe$148/$phpkn$9$Rti.png$"/>$Fig. $24-10$ shows three capacitors connected to a battery of voltage V $=6$ V$.$ The charges on the capacitors are known to be Q $=24?$C for C$1$ and C$2,$ and Q$3=96?$C for C$3.$ What are the values of the capacitances C$1,$ C$2,$ and C$3?$

Possible Answer:A$)$ C$1=6$uF$,$ C$2=12$uF$,$ C$3=16$ uFB$)$ C$1=21$uF$,$ C$2=7$uF$,$ C$3=3$ uFC$)$ C$1=10$uF$,$ C$2=20$uF$,$ C$3=25$uFD$)$ C$1=5$uF$,$ C$2=14$uF$,$ C$3=18$uFE$)$ C$1=8$uF$,$ C$2=16$uF$,$ C$3=24$uF

I think that C$3$ is simply q$/$V which is $16$uF$,$ but shouldn't C$1$ and C$2$ be the same since they are in a series? How are there seperate charges for C$1$ and C$2$