Question: Immediate Normal Time Normal Acitvity Predecessors (days) Cost ($) 9 S 7,000 A 4 $ 5,000 C A 6 S 9,000 D B, C 7

Immediate Normal Time Normal Acitvity

Immediate Normal Time Normal Acitvity Predecessors (days) Cost ($) 9 S 7,000 A 4 $ 5,000 C A 6 S 9,000 D B, C 7 S 3,000 D 5 $ 2,000 FD6S 4,000 LG E, F 7 $ 5,000 $ 35,000 Crash Time Crash Cost Crash Cost Max Crash (days) ($) per day (day) 8 $ 7,800 800 1 3 $ 5,250 2501 5 $ 10,800 1800 Can't crash Activity D $ 2,900 900 3D |???? 600 6 $ 5,500 500 1 What is the "crash cost" for activity F? (Round to the nearest integer and do not include commas or dollar sign, i.e. 1000) 4600 QUESTION 11 1 points Saved The critical path for the project outlined above in Question 10 is: (Enter only the activity letter per box, i.e. "A".) QUESTION 12 1 points Save Answer Refer to the project information in Question 10. Assume indirect costs to be $1,600 per day, and no penalty costs for late completion. A. What activity should be crashed first? F B. What is the net savings from crashing one day of this activity? (Round values to the nearest integer and do not use commas or dollar si gns, i.e. "A" and "1000")

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