Question: Implement the following function in skeleton code lab 1 part 2 . c: / / Let n be the minimum of n 1 and n
Implement the following function in skeleton code labpartc:
Let n be the minimum of n and n where n and n are the number of elements in
arr and arr respectively.
Compare corresponding elements of arr and arr at each of the first n positions.
If arr and arr has the same value in each position:
Return if n n
Return if n n
Return if n n
If arr has a larger value than arr considering the first position from the
beginning at which arr and arr have a different value:
Return
If arr has a smaller value than arr considering the first position from the
beginning at which arr and arr have a different value:
Return
Calculate the sum of the array elements for each array
Print difference between the total sums and comparison of them
If total sums are equal print out The total sums are equal.
If the total sum of the first array is less than the second array, print out The total sum of the first
array is less than the second array
If the total sum of the first array is greater than the second array, print out The total sum of the
first array is greater than the second array
int compareTwoArraysconst int arr const int arr int n int n;
int calculateSumconst int arr int n;
Your task in this part to fill in the missing function definitions in skeleton code labpartc
main function will stay as it is
Sample Run:
Enter the number of elements:
Enter elements:
Array elements:
Enter the number of elements:
Enter elements:
Array elements:
Equal
Total sum of the first array:
Total sum of the second array:
Difference between the total sums:
The total sums are equal.
Computer Engineering Department
TED University
Sample Run :
Enter the number of elements:
Enter elements:
Array elements:
Enter the number of elements:
Enter elements:
Array elements:
Less than
Total sum of the first array:
Total sum of the second array:
Difference between the total sums:
The total sum of the first array is less than the second array
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