import java.util.ArrayList; /* * This program takes two string array lists and finds all the elements in

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Question:

import java.util.ArrayList;
/*
* This program takes two string array lists and finds all the elements in common (i.e. the intersection set)
* For example:
* If list1 contains words: bear porcupine beaver moose wolf
* and list2 contains: beaver otter wolf squirrel
* then the intersection set is:
* beaver wolf
*/
public class SetIntersection
{
/*
* Given two string array lists (a and b) find all string words in common and return
* a new array list containing these words (i.e. the intersection set). If the lists
* have no words in common, then return an empty array list
*/
public static ArrayList intersection(ArrayList a, ArrayList b)
{
//-----------Start below here. To do: approximate lines of code = 8
// Find all common strings between array list a and array list b and store them
// into a new array list. Return a reference to the new array list
// Hint: make use of the method equalsIgnoreCase of class String to test if two strings are equal
// regardless of case e.g. "green" is equal to "Green"

//-----------------End here. Please do not remove this comment. Reminder: no changes outside the todo regions.
}

public static void main(String[] args)
{
ArrayList a = new ArrayList();
ArrayList b = new ArrayList();

// Initialize array lists a and b to some values
a.add("John"); a.add("Paul"); a.add("George"); a.add("Ringo"); a.add("Mick"); a.add("Pete");
b.add("Mick"); b.add("Paul"); b.add("Angus"); b.add("Sting"); b.add("phil");

ArrayList intersectionList = intersection(a,b);
System.out.println(intersectionList);
System.out.println("Expected:[Paul, Mick]");
a.set(1,"Jon"); a.set(4,"Michael");
intersectionList.clear();
System.out.println(intersectionList);
System.out.println("Expected:[]");
}
}