In a ballistic pendulum demonstration gone bad, an mp$=0\mathrm{.}45$ g air gun pellet, fired horizontally with kinetic energy K$0=3\mathrm{.}5$ J$,$ passes straight through the mb$=290$ g Styrofoam pendulum block. If the pendulum swung to a maximum height of $$h$=0\mathrm{.}65$ mm$,$ how much kinetic energy did the pellet have after it emerged from the Styrofoam? Assume the pellet$-$block system is isolated; no FBD or IST is required for this problem.

msmith$99$@hawaii.edu$3$H$73-$A$1-1$C$-42-8614-51480$

$$ Part $($a$)$

Please select the the correct equation that describes the kinetic energy for the pellet after the collision. Treat the interaction between the pellet and block as an inelastic collision, where the bullet interacts with the block for such a short period of time that you can treat the bullet as not deviating from its original path.