In a certain city, 15% of senior citizens have used Uber. To see if an advertising campaign was effective, a researcher samples 200 senior citizens and finds that 40 have used Uber.

Testing at significance level α = .05, find:

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H₀ and H_a:

Group of answer choices

H₀: p = .20

H_a: p < .20

H₀: p = .15

H_a: p > .15

H₀: p = .20

H_a: p > .20

H₀: p = .15

H_a: p < .15

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Sample proportion =

Group of answer choices

.40

.20

.25

.50

.15

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Standard error (S.E.)  assuming H₀ is true =

Group of answer choices

.0006

.025

.16

.85

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z-value =

Group of answer choices

2.33

.05

.025

2.0

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p-value = 

Group of answer choices

approximately 0

.05

.02275

.97615

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Conclusion:

Group of answer choices

50-50 chance advertising campaign was effective

.05 chance advertising campaign was effective

do not reject H₀

reject H₀