In a genetic algorithm problem with a population number of $4,$ the fitness function is e$^-2$f $.$ If the value of f for the instances in the population is as follows:

f$1=0\mathrm{.}4,$ f$2=0\mathrm{.}6,$ f$3=0\mathrm{.}3,$ f$4=0\mathrm{.}8$

How much is the probability that the fourth instance to be selected? $($round it to two decimal places$)$