In a new experimental teaching method, when students have questions in class, they send them to the instructor via a laptop.In a study, of new method, 30 male and 30 female students participated (consider these as two random samples). Of the sampled male students, 17 said they liked the new method than the traditional "raise hand in class" method. Of the sampled female students, 13 said they prefer the new method.

An educator would like to see if the proportions of students who prefer the new method are different between males and females.

Let p1 be the true proportion of male students who prefer new method and p2 be the true proportion of female students who prefer new method.

1. We can use the formula covered in class (i.e., online notes) to construct a confidence interval for difference of two proportions as each sample has at least "X" successes and at least "Y" failures

Optionsfor X: 13, 30, 9, 5

Optionsfor Y : 31, 27, 30, 5

What is the correct answer for X and Y

2. 90% condfidence interval for p1-p2 is ?

3. Based on the confidence interval estimation in part 2, what would be your answer to the educator, who was interested in the outcome of the study?