in actual Racket code please

The list $($all these problems$)$ can be constructed by the form $($cons a $($cons b $($cons c d$)))$ where

a is all,

b is these,

c is problems,

and d is $(),$ the empty list.$$Now write down how you would construct the following list:

$($all $($these problems$))$

$($all $($these$)$ problems$)$

$(($all these$)$ problems$)$

$(($all these problems$))$