Question: In an 1 1 - bit instruction with a 4 - bit address field, one - address instructions need 4 bits for the address and

In an 11-bit instruction with a 4-bit address field, one-address instructions need 4 bits for the address and the remaining 7 bits for the opcode. Since 7 opcode bits can represent 2^7=128 total instructions, and 6 two-address plus 28 zero-address instructions are already used, we can add 94 one-address instructions (128-6-28=94).

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