In an XRD analysis, where Copper X-ray target have been used, below XRD result was obtained.

Please calculate the interplanar spacing for (111) by using the XRD result given below. According to the result given below (111) located at 52.8 degrees.
Please calculate the unit cell parameter "a" for this FCC material.

Transcribed Image Text:

FCC Lattice: First 4 Peaks Cu Ka radiation: 2= 1.54Å Intensity V Label all peaks Place the cursor over a peak to display its position 52.8 * 111 002 022 113 T 20 position / 120 20 40 60 100 FCC Lattice: First 4 Peaks Cu Ka radiation: 2= 1.54Å Intensity V Label all peaks Place the cursor over a peak to display its position 52.8 * 111 002 022 113 T 20 position / 120 20 40 60 100

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The question is to calculate the interplanar distanced and cell parameter a fr... View the full answer