Question: In Assembly language, Write a program with a loop and indirect address that copies a string from source to target. Revising the character order in
In Assembly language, Write a program with a loop and indirect address that copies a string from source to target. Revising the character order in the process. Use the following variables:
source BYTE This is the string that will be reversed, 0
target BYTE SIZEOF source DUP(#)
You may refer to the Programming Exercise #7 on Page 138 of the textbook.
You may study the book example Copying a String on page 127 first. However, this project has three different things from the books example.
- You need two index register. One for the index of source, another for index of target. You can use Register ESI for index of source and Register EDI for index of target
- You will not copy the last character in source, which is null character (the terminator of source string). So the initial value of ESI shall be set as OFFSET target 2 since the target string is stored right after the source string in memory
- After the loop, you need add null character to the end of the target string
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