Question: In C++ Please: Output: Source Code: #include using namespace std; int main(int argc, char const *argv[]) { // TODO: Print the argument count using argc
In C++ Please:

Output:
![argc, char const *argv[]) { // TODO: Print the argument count using](https://dsd5zvtm8ll6.cloudfront.net/si.experts.images/questions/2024/09/66f3053a3836e_61766f30539cc55c.jpg)
Source Code:
#include
using namespace std;
int main(int argc, char const *argv[]) {
// TODO: Print the argument count using argc
// TODO: Using a loop, print out each argument on a line by itself.
return 0;
}
Write a program that shows the contents of argv using a loop. Use the Example Output section to help you understand how to format your output You shall use cout to print messages to the terminal. The starting code defines a series of TODO comments which you can use to formulate your plan and develop your program. Write your program progressively. Compile your program often and check that you're making progress. Make sure your program behaves the way you expect. $ ./command_line_arguments The argument count (argc) is 1 argv[@] is "./command_line_arguments" $ ./command_line_arguments blue yellow orange red The argument count (argc) is 5 argv[@] is "./command_line_arguments" argv[1] is "blue" argv[2] is "yellow" argv[3] is "orange" argv[4] is "red" $ ./command_line_arguments 1 4 8 23 342.2342 45 The argument count (argc) is 7 argv[@] is "./command_line_arguments" argv[1] is "1" argv[2] is "4" argv[3] is "8" argv[4] is "23" argv[5] is "342.2342" argv[6] is "45" $ ./command_line_arguments orange 3 lemon 9 melon 2 The argument count (argc) is 7 argv[@] is "./command_line_arguments" argv[1] is "orange" argv[2] is "3" argv[3] is "lemon" argv[4] is "9" argv[5] is "melon" argv[6] is "2" $
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
